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<title>H. Poincaré, On the dynamics of the electron:
  Extract</title></head>
<body>

<div class="p"><!----></div>

<a href="/poincare/chp/"><img src="icons/contents_motif.gif" alt="icons/contents_motif.gif" /></a>

<div class="p"><!----></div>
<font size="+2"><b><font color="#FFB528">English translation</font></b></font>

<div class="p"><!----></div>

<h1 align="center">On the dynamics of the electron:<br />Introduction, &#167;&#167; 1, 9 </h1>

<div class="p"><!----></div>

<h3 align="center">Henri Poincaré<a href="#tthFtNtAAB" name="tthFrefAAB">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>1</mn></mrow>
</msup>
</mrow></math></a> </h3> 

<div class="p"><!----></div>

<h3 align="center"> </h3> 


<div class="p"><!----></div>

<center>  Introduction.
</center>

<div class="p"><!----></div>
It seems at first that the aberration of light and related optical and
electrical phenomena will provide us with a means of determining the
absolute motion of the Earth, or rather its motion with respect to the
ether, as opposed to its motion with respect to other celestial
bodies. Fresnel pursued this idea, but soon recognized that the
Earth's motion does not alter the laws of refraction and reflection.
Analogous experiments, like that of the water-filled telescope, and
all those considering terms no higher than first order relative to the
aberration, yielded only negative results; the explanation was soon
discovered. But Michelson, who conceived an experiment sensitive to
terms depending on the square of the aberration, failed in turn.

<div class="p"><!----></div>
It appears that this impossibility to detect the absolute motion of
the Earth by experiment may be a general law of nature; we are
naturally inclined to admit this law, which we will call the
<em>Postulate of Relativity</em> and admit without restriction. Whether
or not this postulate, which up to now agrees with experiment, may
later be corroborated or disproved by experiments of greater
precision, it is interesting in any case to ascertain its
consequences.

<div class="p"><!----></div>
An explanation was proposed by Lorentz and FitzGerald, who
introduced the hypothesis of a contraction of all bodies in the
direction of the Earth's motion and proportional to the square of the
aberration. This contraction, which we will call the <em>Lorentzian
  contraction</em>, would explain Michelson's experiment and all others
performed up to now. The hypothesis would become insufficient,
however, if we were to admit the postulate of relativity in full
generality.

<div class="p"><!----></div>
Lorentz then sought to extend his hypothesis and to modify it in order
to obtain perfect agreement with this postulate. This is
what he succeeded in doing in his article entitled
<em>Electromagnetic phenomena in a system moving with any velocity
  smaller that that of light</em> (<em>Proceedings</em> of the Amsterdam
Academy, May 27, 1904).

<div class="p"><!----></div>
The importance of the question persuaded me to take it up in turn; the
results I obtained agree with those of Mr.&#x00A0;Lorentz on all the
significant points. I was led merely to modify and extend them only in
a few details; further on we will see the points of divergence, which
are of secondary importance.

<div class="p"><!----></div>
Lorentz's idea may be summed up like this: if we are able to impress a
translation upon an entire system without modifying
any observable phenomena, it is because the equations of
an electromagnetic medium are unaltered by certain transformations,
which we will call <em>Lorentz transformations</em>. Two systems, one of
which is at rest, the other in translation, become thereby exact
images of each other.

<div class="p"><!----></div>
 Langevin
<a href="#tthFtNtAAC" name="tthFrefAAC">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></math></a>) sought to modify Lorentz's idea; for both authors, the moving
electron takes the form of a flattened ellipsoid. For Lorentz, two
axes of the ellipsoid remain constant, while for Langevin, ellipsoid
volume remains constant. The two scientists also showed that these two
hypotheses are corroborated by Kaufmann's experiments to the same
extent as the original hypothesis of Abraham (rigid-sphere electron).

<div class="p"><!----></div>
The advantage of Langevin's theory is that it requires only
electromagnetic forces, and bonds; it is, however,
incompatible with the postulate of relativity. This is what Lorentz
showed, and this is what I found in turn using a different method,
which calls on principles of group theory.

<div class="p"><!----></div>
We must return therefore to Lorentz's theory, but if we want to do
this and avoid intolerable contradictions, we must posit the
existence of a special force that explains both the contraction, and
the constancy of two of the axes. I sought to determine this force,
and found that <em>it may be assimilated to a constant external
  pressure on the deformable and compressible electron, whose work is
  proportional to the electron's change in volume.</em>

<div class="p"><!----></div>
If the inertia of matter is exclusively of electromagnetic origin, as
generally admitted in the wake of Kaufmann's experiment, and all
forces are of electromagnetic origin (apart from this constant
pressure that I just mentioned), the postulate of relativity may be
established with perfect rigor. This is what I show by a very simple
calculation based on the principle of least action.

<div class="p"><!----></div>
But that is not all. In the article cited above, Lorentz judged it
necessary to extend his hypothesis in such a way that the postulate
remains valid in case there are forces of non-electromagnetic
origin. According to Lorentz, all forces are affected by the Lorentz
transformation (and consequently by a translation) in the same way as
electromagnetic forces.

<div class="p"><!----></div>
It was important to examine this hypothesis closely, and in particular
to ascertain the modifications we would have to apply to the laws
of gravitation.

<div class="p"><!----></div>
We find first of all that it requires us to assume that gravitational
propagation is not instantaneous, but occurs with the speed of
light. One might think that this is reason enough to reject the
hypothesis, since Laplace demonstrated that this cannot be the
case. In reality, however, the effect of this propagation is
compensated in large part by a different cause, in such a way that no
contradiction arises between the proposed law and astronomical
observations.

<div class="p"><!----></div>
Is it possible to find a law satisfying Lorentz's condition, and
reducing to Newton's law whenever the speeds of celestial bodies are
small enough to allow us to neglect their squares (as well as the
product of acceleration and distance) with respect to the square of
the speed of light?

<div class="p"><!----></div>
To this question we must respond in the affirmative, as we will see
later.

<div class="p"><!----></div>
Modified in this way, is the law compatible with astronomical
observations?

<div class="p"><!----></div>
It seems so on first sight, but the question will be settled only
after an extended discussion.

<div class="p"><!----></div>
Suppose, then, that this discussion is settled in favor of the new
hypothesis, what should we conclude? If propagation of attraction
occurs with the speed of light, it could not be a fortuitous
accident. Rather, it must be because it is a function of the ether,
and then we would have to try to penetrate the nature of this
function, and to relate it to other fluid functions.

<div class="p"><!----></div>
We cannot be content with a simple juxtaposition of formulas that
agree with each other by good fortune alone; these formulas must, in a
manner of speaking, interpenetrate. The mind will be satisfied only
when it believes it has perceived the reason for this agreement, and the
belief is strong enough to entertain the illusion that it could have
been predicted.

<div class="p"><!----></div>
But the question may be viewed from a different perspective, better
shown via an analogy. Let us imagine a pre-Copernican astronomer who
reflects on Ptolemy's system; he will notice that for all the planets,
one of two circles - epicycle or deferent - is traversed in the same
time. This fact cannot be due to chance, and consequently between all
the planets there is a mysterious link we can only guess at. 

<div class="p"><!----></div>
Copernicus, however, destroys this apparent link by a simple change in
the coordinate axes that were considered fixed. Each planet now
describes a single circle, and orbital periods become independent
(until Kepler reestablishes the link that was believed to have been
destroyed).

<div class="p"><!----></div>
It is possible that something analogous is taking place here. If we were
to admit the postulate of relativity, we would find the same number in
the law of gravitation and the laws of electromagnetism-the speed of
light-and we would find it again in all other forces of any
origin whatsoever. This state of affairs may be explained in one of
two ways:
either everything in the universe would be of electromagnetic origin,
or this aspect-shared, as it were, by all physical phenomena-would
be a mere epiphenomenon, something due to our methods of
measurement. How do we go about measuring? The first response will
be: we transport objects considered to be invariable solids, one on top of the other.
But that is no longer true in the current theory if we admit the
Lorentzian contraction. In this theory, two lengths are equal, by
definition, if they are traversed by light in equal times.

<div class="p"><!----></div>
Perhaps if we were to abandon this definition Lorentz's theory would
be as fully overthrown as was Ptolemy's system by Copernicus's
intervention. Should that happen some day, it would not prove that
Lorentz's efforts were in vain, because regardless of what one may
think, Ptolemy was useful to Copernicus.

<div class="p"><!----></div>
I, too, have not hesitated to publish these few partial results, even
if at this very moment the discovery of magneto-cathode rays seems to
threaten the entire theory.

<div class="p"><!----></div>

<center>  <b>&#167;&#x00A0;1. - Lorentz Transformation.</b>
</center>

<div class="p"><!----></div>
Lorentz adopted a certain system of units in order to do away with

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mn>4</mn><mi>&pi;</mi></mrow></math> factors in formulas. I will do the same, and in addition, 
select units of length and time in such a way that the speed of light
equals 1. Under these conditions, and denoting electric displacement 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>f</mi></mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>g</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>h</mi></mrow></math>, magnetic intensity 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&alpha;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&beta;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&gamma;</mi></mrow></math>, vector
potential 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>F</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>G</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>H</mi></mrow></math>, scalar potential 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&psi;</mi></mrow></math>, charge density

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&rho;</mi></mrow></math>, electron velocity 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&eta;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&zeta;</mi></mrow></math>, and current

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>u</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>v</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>w</mi></mrow></math>, the fundamental formulas become:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mrow><mo> </mo>
<mtable>
<mtr><mtd columnalign="center"><mrow><mi>u</mi></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>df</mi></mrow>
<mrow><mi>dt</mi></mrow>
</mfrac>
<mo>+</mo><mi>&rho;</mi><mi>&xi;</mi><mo>=</mo>
<mfrac><mrow><mi>d</mi><mi>&gamma;</mi></mrow>
<mrow><mi>dy</mi></mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow><mi>d</mi><mi>&beta;</mi></mrow>
<mrow><mi>dz</mi></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>&alpha;</mi><mo>=</mo>
<mfrac><mrow><mi>dH</mi></mrow>
<mrow><mi>dy</mi></mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow><mi>dG</mi></mrow>
<mrow><mi>dz</mi></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>f</mi><mo>=</mo><mo>-</mo>
<mfrac><mrow><mi>dF</mi></mrow>
<mrow><mi>dt</mi></mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow><mi>d</mi><mi>&psi;</mi></mrow>
<mrow><mi>dx</mi></mrow>
</mfrac>
<mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<mfrac><mrow><mi>d</mi><mi>&alpha;</mi></mrow>
<mrow><mi>dt</mi></mrow>
</mfrac>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>dg</mi></mrow>
<mrow><mi>dz</mi></mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow><mi>dh</mi></mrow>
<mrow><mi>dy</mi></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mi>d</mi><mi>&rho;</mi></mrow>
<mrow><mi>dt</mi></mrow>
</mfrac>
<mo>+</mo><mo>&sum;</mo>
<mfrac><mrow><mi>d</mi><mi>&rho;</mi><mi>&xi;</mi></mrow>
<mrow><mi>dx</mi></mrow>
</mfrac>
<mo>=</mo><mn>0</mn><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>&sum;</mo>
<mfrac><mrow><mi>df</mi></mrow>
<mrow><mi>dx</mi></mrow>
</mfrac>
<mo>=</mo><mi>&rho;</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mi>d</mi><mi>&psi;</mi></mrow>
<mrow><mi>dt</mi></mrow>
</mfrac>
<mo>+</mo><mo>&sum;</mo>
<mfrac><mrow><mi>dF</mi></mrow>
<mrow><mi>dx</mi></mrow>
</mfrac>
<mo>=</mo><mn>0</mn><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow><mi>&#x25A1;</mi></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>&Delta;</mi><mo>-</mo>
<mfrac><mrow>
<msup><mrow><mi>d</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
<mrow>
<msup><mrow><mi>dt</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>=</mo><mo>&sum;</mo>
<mfrac><mrow>
<msup><mrow><mi>d</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
<mrow>
<msup><mrow><mi>dx</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow>
<msup><mrow><mi>d</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
<mrow>
<msup><mrow><mi>dt</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&#x25A1;</mi><mi>&psi;</mi><mo>=</mo><mo>-</mo><mi>&rho;</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&#x25A1;</mi><mi>F</mi><mo>=</mo><mo>-</mo><mi>&rho;</mi><mi>&xi;</mi><mo>.</mo></mrow></mtd></mtr></mtable>

<mo>}</mo></mrow></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>1</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
An elementary particle of matter of volume 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>dxdydz</mi></mrow></math> is acted upon by a
mechanical force, the components of which are derived from the formula:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>X</mi><mo>=</mo><mi>&rho;</mi><mi>f</mi><mo>+</mo><mi>&rho;</mi><mo stretchy="false">(</mo><mi>&eta;</mi><mi>&gamma;</mi><mo>-</mo><mi>&zeta;</mi><mi>&beta;</mi><mo stretchy="false">)</mo><mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>2</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>


These equations admit a remarkable transformation discovered by
Lorentz, which owes its interest to the fact that it explains why
no experiment can inform us of the absolute motion of the
universe. Let us put:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>x</mi><mo>'</mo><mo>=</mo><mi>kl</mi><mo stretchy="false">(</mo><mi>x</mi><mo>+</mo><mi>&epsiv;</mi><mi>t</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>t</mi><mo>'</mo><mo>=</mo><mi>kl</mi><mo stretchy="false">(</mo><mi>t</mi><mo>+</mo><mi>&epsiv;</mi><mi>x</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>y</mi><mo>'</mo><mo>=</mo><mi>&ell;</mi><mi>y</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>z</mi><mo>'</mo><mo>=</mo><mi>&ell;</mi><mi>z</mi><mo>,</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>3</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>


where 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&ell;</mi></mrow></math> and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&epsiv;</mi></mrow></math> are two arbitrary constants, such that
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>k</mi><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><msqrt><mrow><mn>1</mn><mo>-</mo>
<msup><mrow><mi>&epsiv;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></msqrt></mrow>
</mfrac>
<mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Now if we put:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>&#x25A1;</mi><mo>'</mo><mo>=</mo><mo>&sum;</mo>
<mfrac><mrow>
<msup><mrow><mi>d</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
<mrow><mi>dx</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow>
<msup><mrow><mi>d</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
<mrow><mi>dt</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

we will have:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>&#x25A1;</mi><mo>'</mo><mo>=</mo><mi>&#x25A1;</mi>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mo>-</mo><mn>2</mn></mrow>
</msup>
<mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

Let a sphere be carried along with the electron in uniform translation,
and let the equation of this mobile sphere be:

<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mi>x</mi><mo>-</mo><mi>&xi;</mi><mi>t</mi>
<msup><mrow><mo stretchy="false">)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo><mo stretchy="false">(</mo><mi>y</mi><mo>-</mo><mi>&eta;</mi><mi>t</mi>
<msup><mrow><mo stretchy="false">)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo><mo stretchy="false">(</mo><mi>z</mi><mo>-</mo><mi>&zeta;</mi><mi>t</mi>
<msup><mrow><mo stretchy="false">)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>=</mo>
<msup><mrow><mi>r</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

and the volume of the sphere be 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<mfrac><mrow><mn>4</mn></mrow>
<mrow><mn>3</mn></mrow>
</mfrac>
<mi>&pi;</mi>
<msup><mrow><mi>r</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow></math>.<a href="#tthFtNtAAB" name="tthFrefAAB">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>1</mn></mrow>
</msup>
</mrow></math></a>

<div class="p"><!----></div>
The transformation will change the sphere into an ellipsoid, the
equation of which is easy to find. We thus deduce easily from (3):
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>x</mi><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow><mi>&ell;</mi></mrow>
</mfrac>
<mo stretchy="false">(</mo><mi>x</mi><mo>'</mo><mo>-</mo><mi>&epsiv;</mi><mi>t</mi><mo>'</mo><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>t</mi><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow><mi>&ell;</mi></mrow>
</mfrac>
<mo stretchy="false">(</mo><mi>t</mi><mo>'</mo><mo>-</mo><mi>&epsiv;</mi><mi>x</mi><mo>'</mo><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>y</mi><mo>=</mo>
<mfrac><mrow><mi>y</mi><mo>'</mo></mrow>
<mrow><mi>&ell;</mi></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>z</mi><mo>=</mo>
<mfrac><mrow><mi>z</mi><mo>'</mo></mrow>
<mrow><mi>&ell;</mi></mrow>
</mfrac>
<mo>.</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mo stretchy="false">(</mo><mn>3</mn><mo>'</mo><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
The equation of the ellipsoid then becomes:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msup><mrow><mi>k</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo stretchy="false">(</mo><mi>x</mi><mo>'</mo><mo>-</mo><mi>&epsiv;</mi><mi>t</mi><mo>'</mo><mo>-</mo><mi>&xi;</mi><mi>t</mi><mo>'</mo><mo>+</mo><mi>&epsiv;</mi><mi>&xi;</mi><mi>x</mi><mo>'</mo>
<msup><mrow><mo stretchy="false">)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo><mo stretchy="false">(</mo><mi>y</mi><mo>'</mo><mo>-</mo><mi>&eta;</mi><mi>kt</mi><mo>'</mo><mo>+</mo><mi>&eta;</mi><mi>k</mi><mi>&epsiv;</mi><mi>x</mi><mo>'</mo>
<msup><mrow><mo stretchy="false">)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo><mo stretchy="false">(</mo><mi>z</mi><mo>'</mo><mo>-</mo><mi>&zeta;</mi><mi>kt</mi><mo>'</mo><mo>+</mo><mi>&zeta;</mi><mi>k</mi><mi>&epsiv;</mi><mi>x</mi><mo>'</mo>
<msup><mrow><mo stretchy="false">)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>=</mo>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>

<msup><mrow><mi>r</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
This ellipsoid is in uniform motion; for 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi><mo>'</mo><mo>=</mo><mn>0</mn></mrow></math>, it reduces to
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msup><mrow><mi>k</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mi>x</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo stretchy="false">(</mo><mn>1</mn><mo>+</mo><mi>&xi;</mi><mi>&epsiv;</mi>
<msup><mrow><mo stretchy="false">)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo><mo stretchy="false">(</mo><mi>y</mi><mo>'</mo><mo>+</mo><mi>&eta;</mi><mi>k</mi><mi>&epsiv;</mi><mi>x</mi><mo>'</mo>
<msup><mrow><mo stretchy="false">)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo><mo stretchy="false">(</mo><mi>z</mi><mo>'</mo><mo>+</mo><mi>&zeta;</mi><mi>k</mi><mi>&epsiv;</mi><mi>x</mi><mo>'</mo>
<msup><mrow><mo stretchy="false">)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>=</mo>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>

<msup><mrow><mi>r</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

and has a volume:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mn>4</mn></mrow>
<mrow><mn>3</mn></mrow>
</mfrac>
<mi>&pi;</mi>
<msup><mrow><mi>r</mi></mrow><mrow><mn>3</mn></mrow>
</msup>

<mfrac><mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
<mrow><mi>k</mi><mo stretchy="false">(</mo><mn>1</mn><mo>+</mo><mi>&xi;</mi><mi>&epsiv;</mi><mo stretchy="false">)</mo></mrow>
</mfrac>
<mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
If we want electron charge to be unaltered by the transformation, and
if we designate the new charge density 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&rho;</mi><mo>'</mo></mrow></math>, we will find:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>&rho;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo stretchy="false">(</mo><mi>&rho;</mi><mo>+</mo><mi>&epsiv;</mi><mi>&rho;</mi><mi>&xi;</mi><mo stretchy="false">)</mo><mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>4</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
What will be the new velocity components 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi><mo>'</mo></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&eta;</mi><mo>'</mo></mrow></math> and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&zeta;</mi><mo>'</mo></mrow></math>?
We should have:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mtable align="right" width="80%">
<mtr><mtd columnalign="right" columnspan="1"><mrow><mi>&xi;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mi>dx</mi><mo>'</mo></mrow>
<mrow><mi>dt</mi><mo>'</mo></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mi>d</mi><mo stretchy="false">(</mo><mi>x</mi><mo>+</mo><mi>&epsiv;</mi><mi>t</mi><mo stretchy="false">)</mo></mrow>
<mrow><mi>d</mi><mo stretchy="false">(</mo><mi>t</mi><mo>+</mo><mi>&epsiv;</mi><mi>x</mi><mo stretchy="false">)</mo></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mi>&xi;</mi><mo>+</mo><mi>&epsiv;</mi></mrow>
<mrow><mn>1</mn><mo>+</mo><mi>&epsiv;</mi><mi>&xi;</mi></mrow>
</mfrac>
<mo>,</mo></mrow>
</mtd></mtr>
<mtr><mtd columnalign="right" columnspan="1"><mrow><mi>&eta;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mi>dy</mi><mo>'</mo></mrow>
<mrow><mi>dt</mi><mo>'</mo></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mi>dy</mi></mrow>
<mrow><mi>kd</mi><mo stretchy="false">(</mo><mi>t</mi><mo>+</mo><mi>&epsiv;</mi><mi>x</mi><mo stretchy="false">)</mo></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mi>&eta;</mi></mrow>
<mrow><mi>k</mi><mo stretchy="false">(</mo><mn>1</mn><mo>+</mo><mi>&epsiv;</mi><mi>&xi;</mi><mo stretchy="false">)</mo></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&zeta;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mi>&zeta;</mi></mrow>
<mrow><mi>k</mi><mo stretchy="false">(</mo><mn>1</mn><mo>+</mo><mi>&epsiv;</mi><mi>&xi;</mi><mo stretchy="false">)</mo></mrow>
</mfrac>
<mo>,</mo></mrow>
</mtd></mtr>
</mtable>
</mrow>
    </mstyle></math>
</td></tr></table>
<br />

whence:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>&rho;</mi><mo>'</mo><mi>&xi;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo stretchy="false">(</mo><mi>&rho;</mi><mi>&xi;</mi><mo>+</mo><mi>&epsiv;</mi><mi>&rho;</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&rho;</mi><mo>'</mo><mi>&eta;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mi>&rho;</mi><mi>&eta;</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&rho;</mi><mo>'</mo><mi>&zeta;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mi>&rho;</mi><mi>&zeta;</mi><mo>.</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mo stretchy="false">(</mo><mn>4</mn><mo>'</mo><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Here is where I must point out for the first time a difference with
Lorentz. In my notation, Lorentz put (l.c., page 813, formulas 7 and
8):
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>&rho;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><mi>k</mi>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mi>&rho;</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&xi;</mi><mo>'</mo><mo>=</mo>
<msup><mrow><mi>k</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo stretchy="false">(</mo><mi>&xi;</mi><mo>+</mo><mi>&epsiv;</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&eta;</mi><mo>'</mo><mo>=</mo><mi>k</mi><mi>&eta;</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&zeta;</mi><mo>'</mo><mo>=</mo><mi>k</mi><mi>&zeta;</mi><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

In this way we recover the formulas:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>&rho;</mi><mo>'</mo><mi>&xi;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo stretchy="false">(</mo><mi>&rho;</mi><mi>&xi;</mi><mo>+</mo><mi>&epsiv;</mi><mi>&rho;</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&rho;</mi><mo>'</mo><mi>&eta;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mi>&rho;</mi><mi>&eta;</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&rho;</mi><mo>'</mo><mi>&zeta;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mi>&rho;</mi><mi>&zeta;</mi><mo>;</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

although the value of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&rho;</mi><mo>'</mo></mrow></math> differs.

<div class="p"><!----></div>
It is important to notice that the formulas (4) and (
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mn>4</mn><mo>'</mo></mrow></math>) satisfy the
condition of continuity
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mi>d</mi><mi>&rho;</mi><mo>'</mo></mrow>
<mrow><mi>dt</mi><mo>'</mo></mrow>
</mfrac>
<mo>+</mo><mo>&sum;</mo>
<mfrac><mrow><mi>d</mi><mi>&rho;</mi><mo>'</mo><mi>&xi;</mi><mo>'</mo></mrow>
<mrow><mi>dx</mi><mo>'</mo></mrow>
</mfrac>
<mo>=</mo><mn>0</mn><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
To see this, let 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&lambda;</mi></mrow></math> be an undetermined coefficient and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>D</mi></mrow></math> the
Jacobian of
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>t</mi><mo>+</mo><mi>&lambda;</mi><mi>&rho;</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>x</mi><mo>+</mo><mi>&lambda;</mi><mi>&rho;</mi><mi>&xi;</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>y</mi><mo>+</mo><mi>&lambda;</mi><mi>&rho;</mi><mi>&eta;</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>z</mi><mo>+</mo><mi>&lambda;</mi><mi>&rho;</mi><mi>&zeta;</mi></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>5</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>


with respect to 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>x</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>y</mi></mrow></math> and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>z</mi></mrow></math>. It follows that:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>D</mi><mo>=</mo>
<msub><mrow><mi>D</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>+</mo>
<msub><mrow><mi>D</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>&lambda;</mi><mo>+</mo>
<msub><mrow><mi>D</mi></mrow><mrow><mn>2</mn></mrow>
</msub>

<msup><mrow><mi>&lambda;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo>
<msub><mrow><mi>D</mi></mrow><mrow><mn>3</mn></mrow>
</msub>

<msup><mrow><mi>&lambda;</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
<mo>+</mo>
<msub><mrow><mi>D</mi></mrow><mrow><mn>4</mn></mrow>
</msub>

<msup><mrow><mi>&lambda;</mi></mrow><mrow><mn>4</mn></mrow>
</msup>
<mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

with 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>D</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>=</mo><mn>1</mn></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>D</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo>
<mfrac><mrow><mi>d</mi><mi>&rho;</mi></mrow>
<mrow><mi>dt</mi></mrow>
</mfrac>
<mo>+</mo><mo>&sum;</mo>
<mfrac><mrow><mi>d</mi><mi>&rho;</mi><mi>&xi;</mi></mrow>
<mrow><mi>dx</mi></mrow>
</mfrac>
<mo>=</mo><mn>0</mn></mrow></math>.

<div class="p"><!----></div>
Let 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&lambda;</mi><mo>'</mo><mo>=</mo>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>4</mn></mrow>
</msup>
<mi>&rho;</mi><mo>'</mo></mrow></math>;<a href="#tthFtNtAAC" name="tthFrefAAC">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></math></a> then the 4 functions
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>t</mi><mo>'</mo><mo>+</mo><mi>&lambda;</mi><mo>'</mo><mi>&rho;</mi><mo>'</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>x</mi><mo>'</mo><mo>+</mo><mi>&lambda;</mi><mo>'</mo><mi>&rho;</mi><mo>'</mo><mi>&xi;</mi><mo>'</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>y</mi><mo>'</mo><mo>+</mo><mi>&lambda;</mi><mo>'</mo><mi>&rho;</mi><mo>'</mo><mi>&eta;</mi><mo>'</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>z</mi><mo>'</mo><mo>+</mo><mi>&lambda;</mi><mo>'</mo><mi>&rho;</mi><mo>'</mo><mi>&zeta;</mi><mo>'</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mo stretchy="false">(</mo><mn>5</mn><mo>'</mo><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

are related to the functions (5) by the same linear relationships as the
old variables to the new ones. Therefore, if we denote 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>D</mi><mo>'</mo></mrow></math> the Jacobian of
the functions (
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mn>5</mn><mo>'</mo></mrow></math>) with respect to the new variables, it follows
that:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>D</mi><mo>'</mo><mo>=</mo><mi>D</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>D</mi><mo>'</mo><mo>=</mo>
<msub><mrow><mi>D</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>'</mo><mo>+</mo>
<msub><mrow><mi>D</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo><mi>&lambda;</mi><mo>'</mo><mo>+</mo><mo>&#x2026;</mo><mo>+</mo>
<msub><mrow><mi>D</mi></mrow><mrow><mn>4</mn></mrow>
</msub>
<mo>'</mo><mi>&lambda;</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>4</mn></mrow>
</msup>
<mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

and thereby:<a href="#tthFtNtAAD" name="tthFrefAAD">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow></math></a>
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>D</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>'</mo><mo>=</mo>
<msub><mrow><mi>D</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>=</mo><mn>1</mn><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>D</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo><mo>=</mo>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mo>-</mo><mn>4</mn></mrow>
</msup>

<msub><mrow><mi>D</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo><mn>0</mn><mo>=</mo>
<mfrac><mrow><mi>d</mi><mi>&rho;</mi><mo>'</mo></mrow>
<mrow><mi>dt</mi><mo>'</mo></mrow>
</mfrac>
<mo>+</mo><mo>&sum;</mo>
<mfrac><mrow><mi>d</mi><mi>&rho;</mi><mo>'</mo><mi>&xi;</mi><mo>'</mo></mrow>
<mrow><mi>dx</mi><mo>'</mo></mrow>
</mfrac>
<mo>.</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi>
<mtext>Q.E.D.</mtext>
</mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Under Lorentz's hypothesis, this condition would not be met since

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&rho;</mi><mo>'</mo></mrow></math> has a different value.

<div class="p"><!----></div>
We will define the new vector and scalar potentials in such a way as
to satisfy the conditions
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>&#x25A1;</mi><mo>'</mo><mi>&psi;</mi><mo>'</mo><mo>=</mo><mo>-</mo><mi>&rho;</mi><mo>'</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&#x25A1;</mi><mo>'</mo><mi>F</mi><mo>'</mo><mo>=</mo><mo>-</mo><mi>&rho;</mi><mo>'</mo><mi>&xi;</mi><mo>'</mo><mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>6</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
From this we deduce:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>&psi;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow><mi>&ell;</mi></mrow>
</mfrac>
<mo stretchy="false">(</mo><mi>&psi;</mi><mo>+</mo><mi>&epsiv;</mi><mi>F</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>F</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow><mi>&ell;</mi></mrow>
</mfrac>
<mo stretchy="false">(</mo><mi>F</mi><mo>+</mo><mi>&epsiv;</mi><mi>&psi;</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>G</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><mi>&ell;</mi></mrow>
</mfrac>
<mi>G</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>H</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><mi>&ell;</mi></mrow>
</mfrac>
<mi>H</mi><mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>7</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
These formulas differ noticeably from those of Lorentz, although the
divergence stems ultimately from the definitions employed.

<div class="p"><!----></div>
New electric and magnetic fields are now chosen in order to satisfy the
equations
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>f</mi><mo>'</mo><mo>=</mo><mo>-</mo>
<mfrac><mrow><mi>dF</mi><mo>'</mo></mrow>
<mrow><mi>dt</mi><mo>'</mo></mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow><mi>d</mi><mi>&psi;</mi><mo>'</mo></mrow>
<mrow><mi>dx</mi><mo>'</mo></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&alpha;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mi>dH</mi><mo>'</mo></mrow>
<mrow><mi>dy</mi><mo>'</mo></mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow><mi>dG</mi><mo>'</mo></mrow>
<mrow><mi>dz</mi><mo>'</mo></mrow>
</mfrac>
<mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>8</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
It is easy to see that:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mi>d</mi></mrow>
<mrow><mi>dt</mi><mo>'</mo></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow><mi>&ell;</mi></mrow>
</mfrac>
<mrow><mo>(</mo>
<mfrac><mrow><mi>d</mi></mrow>
<mrow><mi>dt</mi></mrow>
</mfrac>
<mo>-</mo><mi>&epsiv;</mi>
<mfrac><mrow><mi>d</mi></mrow>
<mrow><mi>dx</mi></mrow>
</mfrac>
<mo>)</mo></mrow><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mi>d</mi></mrow>
<mrow><mi>dx</mi><mo>'</mo></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow><mi>&ell;</mi></mrow>
</mfrac>
<mrow><mo>(</mo>
<mfrac><mrow><mi>d</mi></mrow>
<mrow><mi>dx</mi></mrow>
</mfrac>
<mo>-</mo><mi>&epsiv;</mi>
<mfrac><mrow><mi>d</mi></mrow>
<mrow><mi>dt</mi></mrow>
</mfrac>
<mo>)</mo></mrow><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mi>d</mi></mrow>
<mrow><mi>dy</mi><mo>'</mo></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><mi>&ell;</mi></mrow>
</mfrac>

<mfrac><mrow><mi>d</mi></mrow>
<mrow><mi>dy</mi></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mi>d</mi></mrow>
<mrow><mi>dz</mi><mo>'</mo></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><mi>&ell;</mi></mrow>
</mfrac>

<mfrac><mrow><mi>d</mi></mrow>
<mrow><mi>dz</mi></mrow>
</mfrac>
</mrow>
    </mstyle></math>
</td></tr></table>
<br />

and we deduce thereby:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mrow><mo> </mo>
<mtable>
<mtr><mtd columnalign="center"><mrow><mn>3</mn><mi>f</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mi>f</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>g</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo stretchy="false">(</mo><mi>g</mi><mo>+</mo><mi>&epsiv;</mi><mi>&gamma;</mi><mo stretchy="false">)</mo><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>h</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo stretchy="false">(</mo><mi>h</mi><mo>-</mo><mi>&epsiv;</mi><mi>&beta;</mi><mo stretchy="false">)</mo><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow><mi>&alpha;</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mi>&alpha;</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&beta;</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo stretchy="false">(</mo><mi>&beta;</mi><mo>-</mo><mi>&epsiv;</mi><mi>h</mi><mo stretchy="false">)</mo><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&gamma;</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo stretchy="false">(</mo><mi>&gamma;</mi><mo>+</mo><mi>&epsiv;</mi><mi>g</mi><mo stretchy="false">)</mo><mo>.</mo></mrow></mtd></mtr></mtable>

<mi>&#x2003;&#x2003;&#x2003;</mi><mo>}</mo></mrow></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>9</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
These formulas are identical to those of Lorentz.

<div class="p"><!----></div>
Our transformation does not alter (1). In fact, the condition of
continuity, as well as (6) and (8) were already featured in (1)
(neglecting the primes).

<div class="p"><!----></div>
Combining (6) with the condition of continuity, we obtain:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mi>d</mi><mi>&psi;</mi><mo>'</mo></mrow>
<mrow><mi>dt</mi><mo>'</mo></mrow>
</mfrac>
<mo>+</mo><mo>&sum;</mo>
<mfrac><mrow><mi>dF</mi><mo>'</mo></mrow>
<mrow><mi>dx</mi><mo>'</mo></mrow>
</mfrac>
<mo>=</mo><mn>0</mn><mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>10</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
It remains for us to establish:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mi>df</mi><mo>'</mo></mrow>
<mrow><mi>dt</mi><mo>'</mo></mrow>
</mfrac>
<mo>+</mo><mi>&rho;</mi><mo>'</mo><mi>&xi;</mi><mo>'</mo><mo>=</mo>
<mfrac><mrow><mi>d</mi><mi>&gamma;</mi><mo>'</mo></mrow>
<mrow><mi>dy</mi><mo>'</mo></mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow><mi>d</mi><mi>&beta;</mi><mo>'</mo></mrow>
<mrow><mi>dz</mi><mo>'</mo></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mi>d</mi><mi>&alpha;</mi><mo>'</mo></mrow>
<mrow><mi>dt</mi><mo>'</mo></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mi>dg</mi><mo>'</mo></mrow>
<mrow><mi>dz</mi><mo>'</mo></mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow><mi>dh</mi><mo>'</mo></mrow>
<mrow><mi>dy</mi><mo>'</mo></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mo>&sum;</mo>
<mfrac><mrow><mi>df</mi><mo>'</mo></mrow>
<mrow><mi>dx</mi><mo>'</mo></mrow>
</mfrac>
<mo>=</mo><mi>&rho;</mi><mo>'</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

and it is easy to see that these are necessary consequences of (6),
(8) and (10).

<div class="p"><!----></div>
We must now compare forces before and after the transformation.

<div class="p"><!----></div>
Let 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>X</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Z</mi></mrow></math> be the force prior to the transformation, and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>X</mi><mo>'</mo></mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Y</mi><mo>'</mo></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Z</mi><mo>'</mo></mrow></math> the force after the transformation, both forces being per
unit volume. In order for 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>X</mi><mo>'</mo></mrow></math> to satisfy the same equations as before
the transformation, we must have:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mtable align="right" width="80%">
<mtr><mtd columnalign="right" columnspan="1"><mrow><mi>X</mi><mo>'</mo></mrow>
</mtd><mtd columnalign="left">
<mrow><mo>=</mo><mi>&rho;</mi><mo>'</mo><mi>f</mi><mo>'</mo><mo>+</mo><mi>&rho;</mi><mo>'</mo><mo stretchy="false">(</mo><mi>&eta;</mi><mo>'</mo><mi>&gamma;</mi><mo>'</mo><mo>-</mo><mi>&zeta;</mi><mo>'</mo><mi>&beta;</mi><mo>'</mo><mo stretchy="false">)</mo><mo>,</mo></mrow>
</mtd></mtr>
<mtr><mtd columnalign="right" columnspan="1"><mrow><mi>Y</mi><mo>'</mo></mrow>
</mtd><mtd columnalign="left">
<mrow><mo>=</mo><mi>&rho;</mi><mo>'</mo><mi>g</mi><mo>'</mo><mo>+</mo><mi>&rho;</mi><mo>'</mo><mo stretchy="false">(</mo><mi>&zeta;</mi><mo>'</mo><mi>&alpha;</mi><mo>'</mo><mo>-</mo><mi>&xi;</mi><mo>'</mo><mi>&gamma;</mi><mo>'</mo><mo stretchy="false">)</mo><mo>,</mo></mrow>
</mtd></mtr>
<mtr><mtd columnalign="right" columnspan="1"><mrow><mi>Z</mi><mo>'</mo></mrow>
</mtd><mtd columnalign="left">
<mrow><mo>=</mo><mi>&rho;</mi><mo>'</mo><mi>h</mi><mo>'</mo><mo>+</mo><mi>&rho;</mi><mo>'</mo><mo stretchy="false">(</mo><mi>&xi;</mi><mo>'</mo><mi>&beta;</mi><mo>'</mo><mo>-</mo><mi>&eta;</mi><mo>'</mo><mi>&alpha;</mi><mo>'</mo><mo stretchy="false">)</mo><mo>,</mo></mrow>
</mtd></mtr>
</mtable>
</mrow>
    </mstyle></math>
</td></tr></table>
<br />

or, replacing all quantities by their values (4), (
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mn>4</mn><mo>'</mo></mrow></math>) and (9), and
in light of (2):
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mrow><mo> </mo>
<mtable>
<mtr><mtd columnalign="center"><mrow><mi>X</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>5</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo stretchy="false">(</mo><mi>X</mi><mo>+</mo><mi>&epsiv;</mi><mo>&sum;</mo><mi>X</mi><mi>&xi;</mi><mo stretchy="false">)</mo><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow><mi>Y</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>5</mn></mrow>
</msup>
</mrow>
</mfrac>
<mi>Y</mi><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow><mi>Z</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>5</mn></mrow>
</msup>
</mrow>
</mfrac>
<mi>Z</mi><mo>.</mo></mrow></mtd></mtr></mtable>

<mi>&#x2003;&#x2003;&#x2003;</mi><mo>}</mo></mrow></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>11</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
Instead of representing the components of force per unit volume by

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, we now let these terms represent the force per unit
electron charge, and we let 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo></mrow></math> represent
the latter force after transformation. It follows that:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo><mi>f</mi><mo>+</mo><mi>&eta;</mi><mi>&gamma;</mi><mo>-</mo><mi>&zeta;</mi><mi>&beta;</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo><mo>=</mo><mi>f</mi><mo>'</mo><mo>+</mo><mi>&eta;</mi><mo>'</mo><mi>&gamma;</mi><mo>'</mo><mo>-</mo><mi>&zeta;</mi><mo>'</mo><mi>&beta;</mi><mo>'</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>X</mi><mo>=</mo><mi>&rho;</mi>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>X</mi><mo>'</mo><mo>=</mo><mi>&rho;</mi>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo><mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

and we obtain the equations:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mrow><mo> </mo>
<mtable>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>k</mi></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>5</mn></mrow>
</msup>
</mrow>
</mfrac>

<mfrac><mrow><mi>&rho;</mi></mrow>
<mrow><mi>&rho;</mi><mo>'</mo></mrow>
</mfrac>
<mo stretchy="false">(</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>+</mo><mi>&epsiv;</mi><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>&xi;</mi><mo stretchy="false">)</mo><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>5</mn></mrow>
</msup>
</mrow>
</mfrac>

<mfrac><mrow><mi>&rho;</mi></mrow>
<mrow><mi>&rho;</mi><mo>'</mo></mrow>
</mfrac>

<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>5</mn></mrow>
</msup>
</mrow>
</mfrac>

<mfrac><mrow><mi>&rho;</mi></mrow>
<mrow><mi>&rho;</mi><mo>'</mo></mrow>
</mfrac>

<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>.</mo></mrow></mtd></mtr></mtable>

<mi>&#x2003;&#x2003;&#x2003;</mi><mo>}</mo></mrow><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mo stretchy="false">(</mo><mn>11</mn><mo>'</mo><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Lorentz found (page 813, equation (10) with different notation):
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mrow><mo> </mo>
<mtable>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>

<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo><mo>-</mo>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mi>&epsiv;</mi><mo stretchy="false">(</mo><mi>&eta;</mi><mo>'</mo><mi>g</mi><mo>'</mo><mo>+</mo><mi>&zeta;</mi><mo>'</mo><mi>h</mi><mo>'</mo><mo stretchy="false">)</mo><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
<mrow><mi>k</mi></mrow>
</mfrac>

<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo><mo>+</mo>
<mfrac><mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mi>&epsiv;</mi></mrow>
<mrow><mi>k</mi></mrow>
</mfrac>
<mi>&xi;</mi><mo>'</mo><mi>g</mi><mo>'</mo><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
<mrow><mi>k</mi></mrow>
</mfrac>

<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo><mo>+</mo>
<mfrac><mrow>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mi>&epsiv;</mi></mrow>
<mrow><mi>k</mi></mrow>
</mfrac>
<mi>&xi;</mi><mo>'</mo><mi>h</mi><mo>'</mo><mo>.</mo></mrow></mtd></mtr></mtable>

<mi>&#x2003;&#x2003;&#x2003;</mi><mo>}</mo></mrow><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mo stretchy="false">(</mo><mn>11</mn>"<mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Before going any further, it is important to locate the source of this
significant divergence. It obviously springs from the fact that the
formulas for 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi><mo>'</mo></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&eta;</mi><mo>'</mo></mrow></math> and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&zeta;</mi><mo>'</mo></mrow></math> are not the same, while the
formulas for the electric and magnetic fields are the same.

<div class="p"><!----></div>
<em>If electron inertia is exclusively of electromagnetic origin,
  and if electrons are subject only to forces of electromagnetic
  origin, then the conditions of equilibrium require that:</em>
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>X</mi><mo>=</mo><mi>Y</mi><mo>=</mo><mi>Z</mi><mo>=</mo><mn>0</mn></mrow>
    </mstyle></math>
</td></tr></table>
<br />

<em>inside the electrons.</em>

<div class="p"><!----></div>
According to (11), these relationships are equivalent to
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>X</mi><mo>'</mo><mo>=</mo><mi>Y</mi><mo>'</mo><mo>=</mo><mi>Z</mi><mo>'</mo><mo>=</mo><mn>0</mn><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
<em>The electron's equilibrium conditions are therefore unaltered by
  the transformation.</em>

<div class="p"><!----></div>
Unfortunately, such a simple hypothesis is inadmissible. In fact, if
we assume 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi><mo>=</mo><mi>&eta;</mi><mo>=</mo><mi>&zeta;</mi><mo>=</mo><mn>0</mn></mrow></math>, the condition 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>X</mi><mo>=</mo><mi>Y</mi><mo>=</mo><mi>Z</mi><mo>=</mo><mn>0</mn></mrow></math> leads
necessarily to 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>f</mi><mo>=</mo><mi>g</mi><mo>=</mo><mi>h</mi><mo>=</mo><mn>0</mn></mrow></math>, and consequently, to

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mo>&sum;</mo>
<mfrac><mrow><mi>df</mi></mrow>
<mrow><mi>dx</mi></mrow>
</mfrac>
<mo>=</mo><mn>0</mn></mrow></math>, i.e., 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&rho;</mi><mo>=</mo><mn>0</mn></mrow></math>. Similar results
obtain for the most general case. We must then admit that in addition to 
electromagnetic forces there are either non-electromagnetic forces or
bonds. Therefore, we need to identify the conditions that these
forces or these bonds must satisfy for electron equilibrium to be
undisturbed by the transformation. This will be the object of an
upcoming section.

<div class="p"><!----></div>

<center><b>&#167;&#x00A0;9. - Hypotheses Concerning Gravitation.</b>
</center>

<div class="p"><!----></div>
In this way Lorentz's theory would fully explain the impossibility of
detecting absolute motion, if all forces were of electromagnetic
origin.

<div class="p"><!----></div>
But there exist other forces to which an electromagnetic origin cannot
be attributed, such as gravitation, for example. It may in fact happen,
that two systems of bodies produce equivalent electromagnetic fields,
i.e., exert the same action on electrified bodies and on currents, and
at the same time, these two systems do not exert the same
gravitational action on Newtonian masses. The gravitational field is
therefore distinct from the electromagnetic field. Lorentz was
obliged thereby to extend his hypothesis with the assumption that
<em>forces of any origin whatsoever, and gravitation in particular,
  are affected by a translation</em> (or, if one prefers, by the Lorentz
transformation) <em>in the same manner as electromagnetic forces</em>.

<div class="p"><!----></div>
It is now appropriate to enter into the details of this hypothesis,
and to examine it more closely. If we want the Newtonian force to be
affected by the Lorentz transformation in this fashion, we can
no longer suppose that it depends only on the relative position of the
attracting and attracted bodies at the instant considered. The
force should also depend on the velocities of the two bodies. And
that is not all: it will be natural to suppose that the force acting
on the attracted body at the instant 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math> depends on the position and
velocity of this body at this same instant 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math>, but it will also depend
on the position and velocity of the <em>attracting</em> body,
not at the instant 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math>, but at <em>an earlier instant</em>, as if
gravitation had taken a certain time to propagate.

<div class="p"><!----></div>
Let us now consider the position of the attracted body at the instant

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>t</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow></math>, and let 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>x</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>y</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>z</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow></math> be its coordinates, and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi></mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&eta;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&zeta;</mi></mrow></math> its velocity components at this instant; let us
consider also the attracting body at the corresponding instant 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>t</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>+</mo><mi>t</mi></mrow></math>, and let its coordinates be 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>x</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>+</mo><mi>x</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>y</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>+</mo><mi>y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>z</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>+</mo><mi>z</mi></mrow></math>, and
its velocity components be 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> at this
instant.

<div class="p"><!----></div>
First we should have a relationship
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>&phiv;</mi><mi>&#x2002;</mi><mo stretchy="false">(</mo><mi>t</mi><mo>,</mo><mi>&#x2002;</mi><mi>x</mi><mo>,</mo><mi>&#x2002;</mi><mi>y</mi><mo>,</mo><mi>&#x2002;</mi><mi>z</mi><mo>,</mo><mi>&#x2002;</mi><mi>&xi;</mi><mo>,</mo><mi>&#x2002;</mi><mi>&eta;</mi><mo>,</mo><mi>&#x2002;</mi><mi>&zeta;</mi><mo>,</mo><mi>&#x2002;</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo><mi>&#x2002;</mi>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo><mi>&#x2003;</mi>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo><mo>=</mo><mn>0</mn></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>1</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>


in order to define the time 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math>. This relationship will define the law of
propagation of gravitational action (I do not constrain myself by any
means to a propagation velocity equal in all directions).

<div class="p"><!----></div>
Now let 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> be the three components of the action
exerted on the attracted body at the instant

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>t</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow></math>;<a href="#tthFtNtAAE" name="tthFrefAAE">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>4</mn></mrow>
</msup>
</mrow></math></a> we want to express 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> as functions of
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>t</mi><mo>,</mo><mi>&#x2002;</mi><mi>x</mi><mo>,</mo><mi>&#x2002;</mi><mi>y</mi><mo>,</mo><mi>&#x2002;</mi><mi>z</mi><mo>,</mo><mi>&#x2002;</mi><mi>&xi;</mi><mo>,</mo><mi>&#x2002;</mi><mi>&eta;</mi><mo>,</mo><mi>&#x2002;</mi><mi>&zeta;</mi><mo>,</mo><mi>&#x2002;</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo><mi>&#x2002;</mi>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo><mi>&#x2003;</mi>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>2</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
What conditions must be satisfied?

<div class="p"><!----></div>
1° The condition (1) should not be altered by transformations of the
Lorentz group.

<div class="p"><!----></div>
2° The components 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> should be affected by
transformations of the Lorentz group in the same manner as the
electromagnetic forces designated by the same letters, i.e., in
accordance with (
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mn>11</mn><mo>'</mo></mrow></math>) of section 1.

<div class="p"><!----></div>
3° When the two bodies are at rest, the ordinary law of attraction
will be recovered.

<div class="p"><!----></div>
It is important to note that in the latter case, the relationship (1)
vanishes, because if the two bodies are at rest the time 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math> plays no role.

<div class="p"><!----></div>
Posed in this fashion the problem is obviously indeterminate.  We will
therefore seek to satisfy to the utmost other, complementary
conditions.

<div class="p"><!----></div>
4°  Since astronomical observations do not seem to show a sensible
deviation from Newton's law, we will choose the solution that differs
the least with this law for small velocities of the two bodies.

<div class="p"><!----></div>
5°  We will make an effort to arrange matters in such a way that 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math>
is always negative. Although we can imagine that the effect of
gravitation requires a certain time in order to propagate, it would be
difficult to understand how this effect could depend on the position
<em>not yet attained</em> by the attracting body.

<div class="p"><!----></div>
There is one case where the indeterminacy of the problem vanishes; it
is the one where the two bodies are in mutual <em>relative</em> rest,
i.e., where
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>&xi;</mi><mo>=</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&eta;</mi><mo>=</mo>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&zeta;</mi><mo>=</mo>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>;</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

this is then the case we will examine first, by supposing
that these velocities are constant, such that the two bodies are
engaged in a common uniform rectilinear translation.

<div class="p"><!----></div>
We may suppose that the 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>x</mi><mo>-</mo></mrow></math>axis is parallel to this
translation, such that 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&eta;</mi><mo>=</mo><mi>&zeta;</mi><mo>=</mo><mn>0</mn></mrow></math>, and we will let

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&epsiv;</mi><mo>=</mo><mo>-</mo><mi>&xi;</mi></mrow></math>.

<div class="p"><!----></div>
If we apply the Lorentz transformation under these conditions, after
the transformation the two bodies will be at rest, and it follows that:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>&xi;</mi><mo>'</mo><mo>=</mo><mi>&eta;</mi><mo>'</mo><mo>=</mo><mi>&zeta;</mi><mo>'</mo><mo>=</mo><mn>0</mn><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
The components 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> should then agree with
Newton's law and we will have, apart from a constant factor:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo><mo>=</mo><mo>-</mo>
<mfrac><mrow><mi>x</mi></mrow>
<mrow><mi>r</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo><mo>=</mo><mo>-</mo>
<mfrac><mrow><mi>y</mi></mrow>
<mrow><mi>r</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo><mo>=</mo><mo>-</mo>
<mfrac><mrow><mi>z</mi></mrow>
<mrow><mi>r</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>r</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>=</mo><mi>x</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo><mi>y</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo><mi>z</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>3</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
But according to section 1 we have:

<div class="p"><!----></div>


<div class="p"><!----></div>
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mtable>
<mtr><mtd columnalign="center"><mrow><mi>x</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>k</mi><mo stretchy="false">(</mo><mi>x</mi><mo>+</mo><mi>&epsiv;</mi><mi>t</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>y</mi><mo>'</mo><mo>=</mo><mi>y</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>z</mi><mo>'</mo><mo>=</mo><mi>z</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>t</mi><mo>'</mo><mo>=</mo><mi>k</mi><mo stretchy="false">(</mo><mi>t</mi><mo>+</mo><mi>&epsiv;</mi><mi>x</mi><mo stretchy="false">)</mo><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<mfrac><mrow><mi>&rho;</mi><mo>'</mo></mrow>
<mrow><mi>&rho;</mi></mrow>
</mfrac>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>k</mi><mo stretchy="false">(</mo><mn>1</mn><mo>+</mo><mi>&xi;</mi><mi>&epsiv;</mi><mo stretchy="false">)</mo><mo>=</mo><mi>k</mi><mo stretchy="false">(</mo><mn>1</mn><mo>-</mo>
<msup><mrow><mi>&epsiv;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo stretchy="false">)</mo><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><mi>k</mi></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>&xi;</mi><mo>=</mo><mo>-</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>&epsiv;</mi><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>k</mi>
<mfrac><mrow><mi>&rho;</mi></mrow>
<mrow><mi>&rho;</mi><mo>'</mo></mrow>
</mfrac>
<mo stretchy="false">(</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>+</mo><mi>&epsiv;</mi><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>&xi;</mi><mo stretchy="false">)</mo><mo>=</mo>
<msup><mrow><mi>k</mi></mrow><mrow><mn>2</mn></mrow>
</msup>

<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo><mn>1</mn><mo>-</mo>
<msup><mrow><mi>&epsiv;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo stretchy="false">)</mo><mo>=</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>k</mi>
<mfrac><mrow><mi>&rho;</mi></mrow>
<mrow><mi>&rho;</mi><mo>'</mo></mrow>
</mfrac>

<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo>
<msub><mrow><mi>kY</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<msub><mrow><mi>kZ</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>.</mo></mrow></mtd></mtr></mtable>

</mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
We have in addition:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>x</mi><mo>+</mo><mi>&epsiv;</mi><mi>t</mi><mo>=</mo><mi>x</mi><mo>-</mo><mi>&xi;</mi><mi>t</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>r</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>=</mo>
<msup><mrow><mi>k</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo stretchy="false">(</mo><mi>x</mi><mo>-</mo><mi>&xi;</mi><mi>t</mi>
<msup><mrow><mo stretchy="false">)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo>
<msup><mrow><mi>y</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo>
<msup><mrow><mi>z</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
    </mstyle></math>
</td></tr></table>
<br />

and
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo>
<mfrac><mrow><mo>-</mo><mi>k</mi><mo stretchy="false">(</mo><mi>x</mi><mo>-</mo><mi>&xi;</mi><mi>t</mi><mo stretchy="false">)</mo></mrow>
<mrow><mi>r</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo>
<mfrac><mrow><mo>-</mo><mi>y</mi></mrow>
<mrow><mi>kr</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo>
<mfrac><mrow><mo>-</mo><mi>z</mi></mrow>
<mrow><mi>kr</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>;</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>4</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>


which may be written:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo>
<mfrac><mrow><mi>dV</mi></mrow>
<mrow><mi>dx</mi></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo>
<mfrac><mrow><mi>dV</mi></mrow>
<mrow><mi>dy</mi></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo>
<mfrac><mrow><mi>dV</mi></mrow>
<mrow><mi>dz</mi></mrow>
</mfrac>
<mo>;</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>V</mi><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><mi>kr</mi><mo>'</mo></mrow>
</mfrac>
<mo>.</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mo stretchy="false">(</mo><mn>4</mn><mo>'</mo><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
It seems at first that the indeterminacy remains, since we made no
hypotheses concerning the value of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math>, i.e., the transmission speed;
and that besides, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>x</mi></mrow></math> is a function of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math>. It is easy to see,
however, that the terms appearing in our formulas, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>x</mi><mo>-</mo><mi>&xi;</mi><mi>t</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>y</mi></mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>z</mi></mrow></math>, do not depend on 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math>.

<div class="p"><!----></div>
We see that if the two bodies translate together, the force acting on
the attracted body is perpendicular to an ellipsoid, at the center of
which lies the attracting body.

<div class="p"><!----></div>
To advance further, we need to look for the <em>invariants of the
  Lorentz group</em>.

<div class="p"><!----></div>
We know that the substitutions of this group (assuming 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&ell;</mi><mo>=</mo><mn>1</mn></mrow></math>) are
linear substitutions that leave unaltered the quadratic form
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo>
<msup><mrow><mi>y</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo>
<msup><mrow><mi>z</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>-</mo>
<msup><mrow><mi>t</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Let us also put:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mtable align="right" width="80%">
<mtr><mtd columnalign="right" columnspan="1"><mrow><mi>&xi;</mi></mrow>
</mtd><mtd columnalign="left">
<mrow><mo>=</mo>
<mfrac><mrow><mi>&delta;</mi><mi>x</mi></mrow>
<mrow><mi>&delta;</mi><mi>t</mi></mrow>
</mfrac>
<mo>,</mo></mrow>
</mtd><mtd columnalign="left">
<mrow><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&eta;</mi></mrow>
</mtd><mtd columnalign="left">
<mrow><mo>=</mo>
<mfrac><mrow><mi>&delta;</mi><mi>y</mi></mrow>
<mrow><mi>&delta;</mi><mi>t</mi></mrow>
</mfrac>
<mo>,</mo></mrow>
</mtd><mtd columnalign="left">
<mrow><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&zeta;</mi></mrow>
</mtd><mtd columnalign="left">
<mrow><mo>=</mo>
<mfrac><mrow><mi>&delta;</mi><mi>z</mi></mrow>
<mrow><mi>&delta;</mi><mi>t</mi></mrow>
</mfrac>
<mo>,</mo></mrow>
</mtd></mtr>
<mtr><mtd columnalign="right" columnspan="1"><mrow>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
</mtd><mtd columnalign="left">
<mrow><mo>=</mo>
<mfrac><mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>x</mi></mrow>
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi></mrow>
</mfrac>
<mo>,</mo></mrow>
</mtd><mtd columnalign="left">
<mrow><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
</mtd><mtd columnalign="left">
<mrow><mo>=</mo>
<mfrac><mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>y</mi></mrow>
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi></mrow>
</mfrac>
<mo>,</mo></mrow>
</mtd><mtd columnalign="left">
<mrow><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
</mtd><mtd columnalign="left">
<mrow><mo>=</mo>
<mfrac><mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>z</mi></mrow>
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi></mrow>
</mfrac>
<mo>;</mo></mrow>
</mtd></mtr>
</mtable>
</mrow>
    </mstyle></math>
</td></tr></table>
<br />

we see that the Lorentz transformation will make 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&delta;</mi><mi>x</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&delta;</mi><mi>y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&delta;</mi><mi>z</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&delta;</mi><mi>t</mi></mrow></math>, and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>x</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>z</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi></mrow></math> undergo the same linear substitutions as 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>x</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>y</mi></mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>z</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math>.

<div class="p"><!----></div>
Let us regard
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mtable>
<mtr><mtd columnalign="center"><mrow><mi>x</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>y</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>z</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>t</mi><msqrt><mrow><mo>-</mo><mn>1</mn></mrow></msqrt><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow><mi>&delta;</mi><mi>x</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&delta;</mi><mi>y</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&delta;</mi><mi>z</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&delta;</mi><mi>t</mi><msqrt><mrow><mo>-</mo><mn>1</mn></mrow></msqrt><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>x</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>y</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>z</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi><msqrt><mrow><mo>-</mo><mn>1</mn></mrow></msqrt><mo>,</mo></mrow></mtd></mtr></mtable>

</mrow>
    </mstyle></math>
</td></tr></table>
<br />

as the coordinates of 3 points 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>P</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>P</mi><mo>'</mo></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>P</mi>"</mrow></math> in space of 4
dimensions. We see that the Lorentz transformation is merely a
rotation in this space about the origin, assumed fixed.
Consequently, we will have no distinct invariants apart from the 6
distances between the 3 points 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>P</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>P</mi><mo>'</mo></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>P</mi>"</mrow></math>, considered separately
and with the origin, or, if one prefers, apart from the two expressions
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo>
<msup><mrow><mi>y</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>+</mo>
<msup><mrow><mi>z</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>-</mo>
<msup><mrow><mi>t</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>x</mi><mi>&delta;</mi><mi>x</mi><mo>+</mo><mi>y</mi><mi>&delta;</mi><mi>y</mi><mo>+</mo><mi>z</mi><mi>&delta;</mi><mi>z</mi><mo>-</mo><mi>t</mi><mi>&delta;</mi><mi>t</mi><mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

or the 4 expressions of like form deduced from an arbitrary
permutation of the 3 points 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>P</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>P</mi><mo>'</mo></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>P</mi>"</mrow></math>.

<div class="p"><!----></div>
But what we seek are invariants that are functions of the 10 variables
(2). Therefore, among the combinations of our 6
invariants we must find those depending only on these 10 variables, i.e., those
that are 0th degree homogeneous with respect both to 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&delta;</mi><mi>x</mi></mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&delta;</mi><mi>y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&delta;</mi><mi>z</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&delta;</mi><mi>t</mi></mrow></math>, and to 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>x</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>y</mi></mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>z</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi></mrow></math>. We will then be left with 4 distinct
invariants:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo>&sum;</mo>
<msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>-</mo>
<msup><mrow><mi>t</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mi>t</mi><mo>-</mo><mo>&sum;</mo><mi>x</mi><mi>&xi;</mi></mrow>
<mrow><msqrt><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msup><mrow><mi>&xi;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></msqrt></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mi>t</mi><mo>-</mo><mo>&sum;</mo><mi>x</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow><msqrt><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msubsup><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
</mrow></msqrt></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo><mi>&xi;</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow><msqrt><mrow><mrow><mo>(</mo><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msup><mrow><mi>&xi;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>)</mo></mrow><mrow><mo>(</mo><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msubsup><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
<mo>)</mo></mrow></mrow></msqrt></mrow>
</mfrac>
<mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>5</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
Next let us see how the force components are transformed; we recall
the equations (11) of section 1, that refer not to the force 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> considered at present, but to the force per unit volume:

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>X</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Z</mi></mrow></math>.

<div class="p"><!----></div>
We designate moreover
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>T</mi><mo>=</mo><mo>&sum;</mo><mi>X</mi><mi>&xi;</mi><mo>;</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

we will see that (11) can be written (
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&ell;</mi><mo>=</mo><mn>1</mn></mrow></math>):
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mrow><mo> </mo>
<mtable>
<mtr><mtd columnalign="center"><mrow><mn>2</mn><mi>X</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>k</mi><mo stretchy="false">(</mo><mi>X</mi><mo>+</mo><mi>&epsiv;</mi><mi>T</mi><mo stretchy="false">)</mo><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>T</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>k</mi><mo stretchy="false">(</mo><mi>T</mi><mo>+</mo><mi>&epsiv;</mi><mi>X</mi><mo stretchy="false">)</mo><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow><mi>Y</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>Y</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>Z</mi><mo>'</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>Z</mi><mo>;</mo></mrow></mtd></mtr></mtable>

<mi>&#x2003;&#x2003;&#x2003;</mi><mo>}</mo></mrow></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>6</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>


in such a way that 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>X</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Z</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>T</mi></mrow></math> undergo the same transformation
as 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>x</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>z</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math>. Consquently, the group invariants will be
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo>&sum;</mo>
<msup><mrow><mi>X</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>-</mo>
<msup><mrow><mi>T</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>&sum;</mo><mi>Xx</mi><mo>-</mo><mi>Tt</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>&sum;</mo><mi>X</mi><mi>&delta;</mi><mi>x</mi><mo>-</mo><mi>T</mi><mi>&delta;</mi><mi>t</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>&sum;</mo><mi>X</mi>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>x</mi><mo>-</mo><mi>T</mi>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

However, it is not 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>X</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Z</mi></mrow></math> that we need, but 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, with
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>&xi;</mi><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

We see that
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow><mi>X</mi></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow><mi>Y</mi></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow><mi>Z</mi></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow><mi>T</mi></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><mi>&rho;</mi></mrow>
</mfrac>
<mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Therefore, the Lorentz transformation will act in the same manner on

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, as on 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>X</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Z</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>T</mi></mrow></math>, except that
these expressions will be multiplied moreover by
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mi>&rho;</mi></mrow>
<mrow><mi>&rho;</mi><mo>'</mo></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><mi>k</mi><mo stretchy="false">(</mo><mn>1</mn><mo>+</mo><mi>&xi;</mi><mi>&epsiv;</mi><mo stretchy="false">)</mo></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mi>&delta;</mi><mi>t</mi></mrow>
<mrow><mi>&delta;</mi><mi>t</mi><mo>'</mo></mrow>
</mfrac>
<mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Likewise, the Lorentz transformation will act in the same way on

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&eta;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&zeta;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mn>1</mn></mrow></math> as on 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&delta;</mi><mi>x</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&delta;</mi><mi>y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&delta;</mi><mi>z</mi></mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&delta;</mi><mi>t</mi></mrow></math>, except that these expressions will be
multiplied moreover by the <em>same</em> factor:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mi>&delta;</mi><mi>t</mi></mrow>
<mrow><mi>&delta;</mi><mi>t</mi><mo>'</mo></mrow>
</mfrac>
<mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><mi>k</mi><mo stretchy="false">(</mo><mn>1</mn><mo>+</mo><mi>&xi;</mi><mi>&epsiv;</mi><mo stretchy="false">)</mo></mrow>
</mfrac>
<mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Next we consider 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>X</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Z</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>T</mi><msqrt><mrow><mo>-</mo><mn>1</mn></mrow></msqrt></mrow></math> as the coordinates of a
fourth point 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>Q</mi></mrow></math>; the invariants will then be functions of the mutual
distances of the five points
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mn>0</mn><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>P</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>P</mi><mo>'</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>P</mi>"<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>Q</mi></mrow>
    </mstyle></math>
</td></tr></table>
<br />

and among these functions we must retain only those that are 0th
degree homogeneous with respect, on one hand, to
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>X</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>Y</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>Z</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>T</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>&delta;</mi><mi>x</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>&delta;</mi><mi>y</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>&delta;</mi><mi>z</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>&delta;</mi><mi>t</mi></mrow>
    </mstyle></math>
</td></tr></table>
<br />

(variables that can be replaced further by 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&eta;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&zeta;</mi></mrow></math>, 1), and on the other hand, with respect
to<a href="#tthFtNtAAF" name="tthFrefAAF">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>5</mn></mrow>
</msup>
</mrow></math></a>
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>x</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>y</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>z</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi></mrow>
    </mstyle></math>
</td></tr></table>
<br />

(variables that can be replaced further by 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 1).

<div class="p"><!----></div>
In this way we find, beyond the four invariants (5), four distinct new
invariants:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mo>&sum;</mo>
<msubsup><mrow><mi>X</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
<mo>-</mo>
<msubsup><mrow><mi>T</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
</mrow>
<mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msup><mrow><mi>&xi;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>x</mi><mo>-</mo>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi></mrow>
<mrow><msqrt><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msup><mrow><mi>&xi;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></msqrt></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>

<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>-</mo>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow><msqrt><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msup><mrow><mi>&xi;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></msqrt><msqrt><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msubsup><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
</mrow></msqrt></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>&xi;</mi><mo>-</mo>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msup><mrow><mi>&xi;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>7</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>


The latter invariant is always null according to the definition of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>.

<div class="p"><!----></div>
These terms being settled, what conditions must be satisfied?

<div class="p"><!----></div>
1° The first term of (1), defining the velocity of propagation, has to
be a function of the 4 invariants (5).

<div class="p"><!----></div>
A wealth of hypotheses can obviously be entertained, of which we will
examine only two:

<div class="p"><!----></div>
A) We can have
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo>&sum;</mo>
<msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>-</mo>
<msup><mrow><mi>t</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>=</mo>
<msup><mrow><mi>r</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>-</mo>
<msup><mrow><mi>t</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>=</mo><mn>0</mn><mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

from whence 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi><mo>=</mo><mo>&PlusMinus;</mo><mi>r</mi></mrow></math>, and, since 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math> has to be negative, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi><mo>=</mo><mo>-</mo><mi>r</mi></mrow></math>.
This means that the velocity of propagation is equal to that of light.
It seems at first that this hypothesis ought to be rejected outright.
Laplace showed in effect that the propagation is either instantaneous
or much faster than that of light. However, Laplace examined the
hypothesis of finite propagation velocity <em>ceteris non mutatis</em>;
here, on the contrary, this hypothesis is conjoined with many others,
and it may be that between them a more or less perfect compensation
takes place. The application of the Lorentz transformation has already
provided us with numerous examples of this.

<div class="p"><!----></div>
B) We can have
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mi>t</mi><mo>-</mo><mo>&sum;</mo><mi>x</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow><msqrt><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msubsup><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
</mrow></msqrt></mrow>
</mfrac>
<mo>=</mo><mn>0</mn><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>t</mi><mo>=</mo><mo>&sum;</mo><mi>x</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />
 
The propagation velocity is therefore much faster
than that of light, but in certain cases 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math> could be positive, which,
as we mentioned, seems hardly admissible.<a href="#tthFtNtAAG" name="tthFrefAAG">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>6</mn></mrow>
</msup>
</mrow></math></a> <em>We will therefore stick with
  hypothesis</em> (A).

<div class="p"><!----></div>
2° The four invariants (7) ought to be functions of the invariants (5).

<div class="p"><!----></div>
3° When the two bodies are at absolute rest, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>
ought to have the values given by Newton's law, and when they are at
relative rest, the values given by (4).

<div class="p"><!----></div>
For the case of absolute rest, the first two invariants (7) ought to reduce to
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo>&sum;</mo>
<msubsup><mrow><mi>X</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>x</mi><mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

or, by Newton's law, to
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>r</mi></mrow><mrow><mn>4</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mo>-</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><mi>r</mi></mrow>
</mfrac>
<mo>;</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

in addition, according to hypothesis (A), the 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow><mn>2</mn></mrow><mrow>
<mtext>d</mtext>
</mrow>
</msup>
</mrow></math> and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow><mn>3</mn></mrow><mrow>
<mtext>rd</mtext>
</mrow>
</msup>
</mrow></math> invariants in (5) become:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mo>-</mo><mi>r</mi><mo>-</mo><mo>&sum;</mo><mi>x</mi><mi>&xi;</mi></mrow>
<mrow><msqrt><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msup><mrow><mi>&xi;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></msqrt></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mo>-</mo><mi>r</mi><mo>-</mo><mo>&sum;</mo><mi>x</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow><msqrt><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msubsup><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
</mrow></msqrt></mrow>
</mfrac>
<mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

that is, for absolute rest,
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo>-</mo><mi>r</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mo>-</mo><mi>r</mi><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
We may therefore admit, <em>for example</em>, that the first two
invariants in (7) reduce to<a href="#tthFtNtAAH" name="tthFrefAAH">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>7</mn></mrow>
</msup>
</mrow></math></a>
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow>
<msup><mrow><mo>(</mo><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msubsup><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
<mo>)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
<mrow>
<msup><mrow><mo>(</mo><mi>r</mi><mo>+</mo><mo>&sum;</mo><mi>x</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>)</mo></mrow><mrow><mn>4</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>-</mo>
<mfrac><mrow><msqrt><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msubsup><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
</mrow></msqrt></mrow>
<mrow><mi>r</mi><mo>+</mo><mo>&sum;</mo><mi>x</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
</mfrac>
<mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

although other combinations are possible.

<div class="p"><!----></div>
A choice must be made among these combinations, and furthermore, we
need a 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow><mn>3</mn></mrow><mrow>
<mtext>rd</mtext>
</mrow>
</msup>
</mrow></math> equation in order to define 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>. In making such a choice, we should try to come as close as
possible to Newton's law. Let us see what happens when we neglect the
squares of the velocities 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&eta;</mi></mrow></math>, etc. (still letting 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi><mo>=</mo><mo>-</mo><mi>r</mi></mrow></math>).
The 4 invariants (5) then become:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mn>0</mn><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>-</mo><mi>r</mi><mo>-</mo><mo>&sum;</mo><mi>x</mi><mi>&xi;</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>-</mo><mi>r</mi><mo>-</mo><mo>&sum;</mo><mi>x</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mn>1</mn></mrow>
    </mstyle></math>
</td></tr></table>
<br />

and the 4 invariants (7) become:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo>&sum;</mo>
<msubsup><mrow><mi>X</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo><mi>x</mi><mo>+</mo><mi>&xi;</mi><mi>r</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>-</mo><mi>&xi;</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mn>0</mn><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Before we can make a comparison with Newton's law, another
transformation is required. In the case under consideration, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>x</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>+</mo><mi>x</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>y</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>+</mo><mi>y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>z</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>+</mo><mi>z</mi></mrow></math>, represent the coordinates of the attracting body at the
instant 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>t</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>+</mo><mi>t</mi></mrow></math>, and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>r</mi><mo>=</mo><msqrt><mrow><mo>&sum;</mo>
<msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></msqrt></mrow></math>. With Newton's law we
have to consider the coordinates of the attracting body 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>x</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>+</mo>
<msub><mrow><mi>x</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>y</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>+</mo>
<msub><mrow><mi>y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>z</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>+</mo>
<msub><mrow><mi>z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> at the instant 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>t</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow></math>, and the distance 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>r</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo><msqrt><mrow><mo>&sum;</mo>
<msup><mrow><mi>x</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></msqrt></mrow></math>.

<div class="p"><!----></div>
We may neglect the square of the time 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math> required for propagation,
and proceed, consequently, as if the motion were uniform; we then
have:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>x</mi><mo>=</mo>
<msub><mrow><mi>x</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>+</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>y</mi><mo>=</mo>
<msub><mrow><mi>y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>+</mo>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>z</mi><mo>=</mo>
<msub><mrow><mi>z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>+</mo>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>r</mi><mo stretchy="false">(</mo><mi>r</mi><mo>-</mo>
<msub><mrow><mi>r</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo><mo>=</mo><mo>&sum;</mo><mi>x</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi><mo>;</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

or, since 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi><mo>=</mo><mo>-</mo><mi>r</mi></mrow></math>,
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>x</mi><mo>=</mo>
<msub><mrow><mi>x</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>-</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>r</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>y</mi><mo>=</mo>
<msub><mrow><mi>y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>-</mo>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>r</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>z</mi><mo>=</mo>
<msub><mrow><mi>z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>-</mo>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>r</mi><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>r</mi><mo>=</mo>
<msub><mrow><mi>r</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>-</mo><mo>&sum;</mo><mi>x</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>;</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

such that our 4 invariants (5) become:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mn>0</mn><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>-</mo>
<msub><mrow><mi>r</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>+</mo><mo>&sum;</mo><mi>x</mi><mo stretchy="false">(</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>-</mo><mi>&xi;</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>-</mo>
<msub><mrow><mi>r</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mn>1</mn></mrow>
    </mstyle></math>
</td></tr></table>
<br />

and our 4 invariants (7) become:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo>&sum;</mo>
<msubsup><mrow><mi>X</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">[</mo>
<msub><mrow><mi>x</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>+</mo><mo stretchy="false">(</mo><mi>&xi;</mi><mo>-</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo>
<msub><mrow><mi>r</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">]</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>-</mo><mi>&xi;</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mn>0</mn><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

In the second of these expressions I wrote 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>r</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> instead of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>r</mi></mrow></math>,
because 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>r</mi></mrow></math> is multiplied by 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi><mo>-</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, and because I neglect the
square of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi></mrow></math>.

<div class="p"><!----></div>
For these 4 invariants (7), Newton's law would yield
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msubsup><mrow><mi>r</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>4</mn></mrow></msubsup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mo>-</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msub><mrow><mi>r</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow><mo>&sum;</mo>
<msub><mrow><mi>x</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo><mi>&xi;</mi><mo>-</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo></mrow>
<mrow>
<msubsup><mrow><mi>r</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi>
<mfrac><mrow><mo>&sum;</mo>
<msub><mrow><mi>x</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo><mi>&xi;</mi><mo>-</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo></mrow>
<mrow>
<msubsup><mrow><mi>r</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>3</mn></mrow></msubsup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mn>0</mn><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Therefore, if we designate the 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow><mn>2</mn></mrow><mrow>
<mtext>nd</mtext>
</mrow>
</msup>
</mrow></math> and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow><mn>3</mn></mrow><mrow>
<mtext>rd</mtext>
</mrow>
</msup>
</mrow></math> of
the invariants (5) as 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>A</mi></mrow></math> and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>B</mi></mrow></math>, and the first 3 invariants of (7)
as 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>M</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>N</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>P</mi></mrow></math>, we will satisfy Newton's law to first-order terms in
the square of velocity by setting:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>M</mi><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>4</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>N</mi><mo>=</mo>
<mfrac><mrow><mo>+</mo><mi>A</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>P</mi><mo>=</mo>
<mfrac><mrow><mi>A</mi><mo>-</mo><mi>B</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>8</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
This solution is not unique. Let 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>C</mi></mrow></math> be the 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow><mn>4</mn></mrow><mrow>
<mtext>th</mtext>
</mrow>
</msup>
</mrow></math> invariant in (5);

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>C</mi><mo>-</mo><mn>1</mn></mrow></math> is of the order of the square of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi></mrow></math>, and it is the same with

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mo stretchy="false">(</mo><mi>A</mi><mo>-</mo><mi>B</mi>
<msup><mrow><mo stretchy="false">)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></math>.

<div class="p"><!----></div>
The solution (8) appears at first to be the simplest, nevertheless, it
may not be adopted. In fact, since 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>M</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>N</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>P</mi></mrow></math> are functions of

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo><mo>&sum;</mo>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>&xi;</mi></mrow></math>, the values of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> can be drawn from these three equations (8), but in
certain cases these values would become imaginary.

<div class="p"><!----></div>
To avoid this difficulty we will proceed in a different manner. Let us
put:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><msqrt><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msup><mrow><mi>&xi;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></msqrt></mrow>
</mfrac>
<mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><msqrt><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msubsup><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
</mrow></msqrt></mrow>
</mfrac>
<mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

which is justified by analogy with the notation
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>k</mi><mo>=</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow><msqrt><mrow><mn>1</mn><mo>-</mo><mo>&sum;</mo>
<msup><mrow><mi>&xi;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></msqrt></mrow>
</mfrac>
</mrow>
    </mstyle></math>
</td></tr></table>
<br />

featured in the Lorentz substitution.

<div class="p"><!----></div>
In this case, and in light of the condition 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mo>-</mo><mi>r</mi><mo>=</mo><mi>t</mi></mrow></math>, the invariants (5) become:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mn>0</mn><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>A</mi><mo>=</mo><mo>-</mo>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo stretchy="false">(</mo><mi>r</mi><mo>+</mo><mo>&sum;</mo><mi>x</mi><mi>&xi;</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>B</mi><mo>=</mo><mo>-</mo>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo><mi>r</mi><mo>+</mo><mo>&sum;</mo><mi>x</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;</mi><mi>C</mi><mo>=</mo>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>

<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo><mn>1</mn><mo>-</mo><mo>&sum;</mo><mi>&xi;</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Moreover, we notice that the following systems of quantities:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mtable>
<mtr><mtd columnalign="center"><mrow><mi>x</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>y</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>z</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>-</mo><mi>r</mi><mo>=</mo><mi>t</mi><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>

<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>

<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>

<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>

<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mi>&xi;</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mi>&eta;</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mi>&zeta;</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>

<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>

<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>

<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd></mtr></mtable>

</mrow>
    </mstyle></math>
</td></tr></table>
<br />

undergo the <em>same</em> linear substitutions when the transformations
of the Lorentz group are applied to them. We are led thereby to put:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mrow><mo> </mo>
<mtable>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>x</mi>
<mfrac><mrow><mi>&alpha;</mi></mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow>
</mfrac>
<mo>+</mo><mi>&xi;</mi><mi>&beta;</mi><mo>+</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>

<mfrac><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow>
</mfrac>
<mi>&gamma;</mi><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>y</mi>
<mfrac><mrow><mi>&alpha;</mi></mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow>
</mfrac>
<mo>+</mo><mi>&eta;</mi><mi>&beta;</mi><mo>+</mo>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>

<mfrac><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow>
</mfrac>
<mi>&gamma;</mi><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>z</mi>
<mfrac><mrow><mi>&alpha;</mi></mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow>
</mfrac>
<mo>+</mo><mi>&zeta;</mi><mi>&beta;</mi><mo>+</mo>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>

<mfrac><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow>
</mfrac>
<mi>&gamma;</mi><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mo>-</mo><mi>r</mi>
<mfrac><mrow><mi>&alpha;</mi></mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow>
</mfrac>
<mo>+</mo><mi>&beta;</mi><mo>+</mo>
<mfrac><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow>
</mfrac>
<mi>&gamma;</mi><mo>.</mo></mrow></mtd></mtr></mtable>

<mi>&#x2003;&#x2003;&#x2003;</mi><mo>}</mo></mrow></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>9</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>


It is clear that if 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&alpha;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&beta;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&gamma;</mi></mrow></math> are invariants, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> will satisfy the fundamental condition, i.e., the
Lorentz transformations will make them undergo an appropriate linear
substitution.

<div class="p"><!----></div>
However, for equations (9) to be compatible we must have
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>&xi;</mi><mo>-</mo>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo><mn>0</mn><mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

which becomes, replacing 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> with their values
in (9) and multiplying by 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msubsup><mrow><mi>k</mi></mrow><mrow><mn>0</mn> </mrow>
<mrow><mn>2</mn></mrow></msubsup>
</mrow></math>:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo>-</mo><mi>A</mi><mi>&alpha;</mi><mo>-</mo><mi>&beta;</mi><mo>-</mo><mi>C</mi><mi>&gamma;</mi><mo>=</mo><mn>0</mn><mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>10</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>


What we would like is that the values of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> remain in
line with Newton's law when we neglect (as above) the squares of
velocities 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi></mrow></math>, etc.&#x00A0;with respect to the square of the velocity of
light, and the products of acceleration and distance.

<div class="p"><!----></div>
We could select
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mi>&beta;</mi><mo>=</mo><mn>0</mn><mo>,</mo><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mi>&gamma;</mi><mo>=</mo><mo>-</mo>
<mfrac><mrow><mi>A</mi><mi>&alpha;</mi></mrow>
<mrow><mi>C</mi></mrow>
</mfrac>
<mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

To the adopted order of approximation, we obtain
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
<mo>=</mo>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo><mn>1</mn><mo>,</mo><mi>&#x2002;</mi><mi>C</mi><mo>=</mo><mn>1</mn><mo>,</mo><mi>&#x2002;</mi><mi>A</mi><mo>=</mo><mo>-</mo>
<msub><mrow><mi>r</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>+</mo><mo>&sum;</mo><mi>x</mi><mo stretchy="false">(</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>-</mo><mi>&xi;</mi><mo stretchy="false">)</mo><mo>,</mo><mi>&#x2003;</mi><mi>B</mi><mo>=</mo><mo>-</mo>
<msub><mrow><mi>r</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>,</mo><mi>&#x2002;</mi><mi>x</mi><mo>=</mo>
<msub><mrow><mi>x</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>+</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>t</mi><mo>=</mo>
<msub><mrow><mi>x</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>-</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>r</mi><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
The 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow><mn>1</mn></mrow><mrow>
<mtext>st</mtext>
</mrow>
</msup>
</mrow></math> equation in (9) then becomes
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo><mi>&alpha;</mi><mo stretchy="false">(</mo><mi>x</mi><mo>-</mo><mi>A</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo><mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
But if the square of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi></mrow></math> is neglected, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>A</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> can be replaced by

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mo>-</mo>
<msub><mrow><mi>r</mi></mrow><mrow><mn>1</mn></mrow>
</msub>

<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, or by 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mo>-</mo><mi>r</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, which yields:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo><mi>&alpha;</mi><mo stretchy="false">(</mo><mi>x</mi><mo>+</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>r</mi><mo stretchy="false">)</mo><mo>=</mo><mi>&alpha;</mi>
<msub><mrow><mi>x</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Newton's law would yield
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo><mo>-</mo>
<mfrac><mrow>
<msub><mrow><mi>x</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow>
<msubsup><mrow><mi>r</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>3</mn></mrow></msubsup>
</mrow>
</mfrac>
<mo>.</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />


<div class="p"><!----></div>
Consequently, we must select a value for the invariant 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&alpha;</mi></mrow></math> which
reduces to 

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mo>-</mo>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msubsup><mrow><mi>r</mi></mrow><mrow><mn>1</mn> </mrow>
<mrow><mn>3</mn></mrow></msubsup>
</mrow>
</mfrac>
</mrow></math> in the adopted order of
approximation, that is, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
</mrow></math>. Equations (9) will
become:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mrow><mo> </mo>
<mtable>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>x</mi></mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>

<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>-</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>

<mfrac><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow>
</mfrac>

<mfrac><mrow><mi>A</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
<mi>C</mi></mrow>
</mfrac>
<mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>y</mi></mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>

<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>-</mo>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>

<mfrac><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow>
</mfrac>

<mfrac><mrow><mi>A</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
<mi>C</mi></mrow>
</mfrac>
<mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>z</mi></mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>

<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>-</mo>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>

<mfrac><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow>
</mfrac>

<mfrac><mrow><mi>A</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
<mi>C</mi></mrow>
</mfrac>
<mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>T</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mo>-</mo>
<mfrac><mrow><mi>r</mi></mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>

<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>0</mn></mrow>
</msub>
</mrow>
</mfrac>

<mfrac><mrow><mi>A</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
<mi>C</mi></mrow>
</mfrac>
<mo>.</mo></mrow></mtd></mtr></mtable>

<mi>&#x2003;&#x2003;&#x2003;</mi><mo>}</mo></mrow></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>11</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
We notice first that the corrected attraction is composed of two
components: one parallel to the vector joining the positions of the
two bodies, the other parallel to the velocity of the attracting body.

<div class="p"><!----></div>
Remember that when we speak of the position or velocity of the
attracting body, this refers to its position or velocity at the instant
the gravitational wave takes off; for the attracted body, on the
contrary, this refers to the position or velocity at the instant the
gravitational wave arrives, assuming that this wave propagates
with the velocity of light.

<div class="p"><!----></div>
I believe it would be premature to seek to push the discussion of
these formulas further; I will therefore confine myself to a few
remarks.

<div class="p"><!----></div>
1° The solutions (11) are not unique; we may, in fact, replace the
the global factor 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
</mrow></math> by
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>+</mo><mo stretchy="false">(</mo><mi>C</mi><mo>-</mo><mn>1</mn><mo stretchy="false">)</mo>
<msub><mrow><mi>f</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>&#x2002;</mi><mo stretchy="false">(</mo><mi>A</mi><mo>,</mo><mi>&#x2002;</mi><mi>B</mi><mo>,</mo><mi>&#x2002;</mi><mi>C</mi><mo stretchy="false">)</mo><mo>+</mo><mo stretchy="false">(</mo><mi>A</mi><mo>-</mo><mi>B</mi>
<msup><mrow><mo stretchy="false">)</mo></mrow><mrow><mn>2</mn></mrow>
</msup>

<msub><mrow><mi>f</mi></mrow><mrow><mn>2</mn></mrow>
</msub>
<mi>&#x2002;</mi><mo stretchy="false">(</mo><mi>A</mi><mo>,</mo><mi>&#x2002;</mi><mi>B</mi><mo>,</mo><mi>&#x2002;</mi><mi>C</mi><mo stretchy="false">)</mo><mo>,</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

where 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>f</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math> and 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>f</mi></mrow><mrow><mn>2</mn></mrow>
</msub>
</mrow></math> are arbitrary functions of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>A</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>B</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>C</mi></mrow></math>.
Alternatively, we may forgo setting 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&beta;</mi></mrow></math> to zero, but add any
complementary terms to 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&alpha;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&beta;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&gamma;</mi></mrow></math> that satisfy
condition (10) and are of second order with respect to the

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi></mrow></math> for 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&alpha;</mi></mrow></math>, and of first order for 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&beta;</mi></mrow></math> and

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&gamma;</mi></mrow></math>.

<div class="p"><!----></div>
2° The first equation in (11) may be written:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>=</mo>
<mfrac><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
<mi>C</mi></mrow>
</mfrac>
<mrow><mo>[</mo><mi>x</mi><mrow><mo>(</mo><mn>1</mn><mo>-</mo><mo>&sum;</mo><mi>&xi;</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>)</mo></mrow><mo>+</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mrow><mo>(</mo><mi>r</mi><mo>+</mo><mo>&sum;</mo><mi>x</mi><mi>&xi;</mi><mo>)</mo></mrow><mo>]</mo></mrow><mi>&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;&#x2003;</mi><mo stretchy="false">(</mo><mn>11</mn><mo>'</mo><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>
<br />

and the quantity in brackets itself may be written:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mi>x</mi><mo>+</mo><mi>r</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo><mo>+</mo><mi>&eta;</mi><mo stretchy="false">(</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>y</mi><mo>-</mo><mi>x</mi>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo><mo>+</mo><mi>&zeta;</mi><mo stretchy="false">(</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>z</mi><mo>-</mo><mi>x</mi>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo><mo>,</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>12</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>


such that the total force may be separated into three components
corresponding to the three parentheses of expression (12); the first
component is vaguely analogous to the mechanical force due to the
electric field, the two others to the mechanical force due to the
magnetic field; to extend the analogy I may, in light of the first
remark, replace 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<mfrac><mrow><mn>1</mn></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
</mrow></math> in (11) by

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<mfrac><mrow><mi>C</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
</mrow></math>, in such a way that 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>
are linear functions of the attracted body's velocity 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&eta;</mi></mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&zeta;</mi></mrow></math>, since 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>C</mi></mrow></math> has vanished from the denominator of (
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mn>11</mn><mo>'</mo></mrow></math>).

<div class="p"><!----></div>
Next we put:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mrow><mo> </mo>
<mtable>
<mtr><mtd columnalign="center"><mrow><mn>3</mn>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo><mi>x</mi><mo>+</mo><mi>r</mi>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>&lambda;</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo><mi>y</mi><mo>+</mo><mi>r</mi>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>&mu;</mi><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo><mi>z</mi><mo>+</mo><mi>r</mi>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>&nu;</mi><mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>z</mi><mo>-</mo>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>y</mi><mo stretchy="false">)</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>&lambda;</mi><mo>'</mo><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo>
<msub><mrow><mi>&zeta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>x</mi><mo>-</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>z</mi><mo stretchy="false">)</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>&mu;</mi><mo>'</mo><mo>,</mo></mrow></mtd><mtd columnalign="left"><mrow><mi>&#x2003;&#x2003;&#x2003;</mi>
<msub><mrow><mi>k</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">(</mo>
<msub><mrow><mi>&xi;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>y</mi><mo>-</mo><mi>x</mi>
<msub><mrow><mi>&eta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo stretchy="false">)</mo></mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo><mi>&nu;</mi><mo>'</mo><mo>;</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow></mrow></mtd></mtr></mtable>

<mo>}</mo></mrow></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>13</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>


and since 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>C</mi></mrow></math> has vanished from the denominator of (
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mn>11</mn><mo>'</mo></mrow></math>), it
will follow that:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mrow><mo> </mo>
<mtable>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>X</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>&lambda;</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow><mi>&eta;</mi><mi>&nu;</mi><mo>'</mo><mo>-</mo><mi>&zeta;</mi><mi>&mu;</mi><mo>'</mo></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>Y</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>&mu;</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow><mi>&zeta;</mi><mi>&lambda;</mi><mo>'</mo><mo>-</mo><mi>&xi;</mi><mi>&nu;</mi><mo>'</mo></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>,</mo></mrow></mtd></mtr>
<mtr><mtd columnalign="center"><mrow>
<msub><mrow><mi>Z</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></mtd><mtd columnalign="left"><mrow><mo>=</mo>
<mfrac><mrow><mi>&nu;</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>-</mo>
<mfrac><mrow><mi>&xi;</mi><mi>&mu;</mi><mo>'</mo><mo>-</mo><mi>&eta;</mi><mi>&lambda;</mi><mo>'</mo></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
<mo>;</mo></mrow></mtd></mtr></mtable>

<mi>&#x2003;&#x2003;&#x2003;</mi><mo>}</mo></mrow></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>14</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>


and we will have moreover:
<br />
<table width="100%"><tr><td align="center">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>=</mo><mo>&sum;</mo>
<msup><mrow><mi>&lambda;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>-</mo><mo>&sum;</mo><mi>&lambda;</mi><mo>'</mo>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
<mo>.</mo></mrow>
    </mstyle></math></td><td width="1">
    <math xmlns="http://www.w3.org/1998/Math/MathML">
    <mstyle displaystyle="true"><mrow><mo stretchy="false">(</mo><mn>15</mn><mo stretchy="false">)</mo></mrow>
    </mstyle></math>
</td></tr></table>



<div class="p"><!----></div>
Now 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&lambda;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&mu;</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&nu;</mi></mrow></math>, or 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<mfrac><mrow><mi>&lambda;</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
</mrow></math>,

<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<mfrac><mrow><mi>&mu;</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<mfrac><mrow><mi>&nu;</mi></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
</mrow></math>, is
an electric field of sorts, while 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&lambda;</mi><mo>'</mo></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&mu;</mi><mo>'</mo></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&nu;</mi><mo>'</mo></mrow></math>, or
rather 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<mfrac><mrow><mi>&lambda;</mi><mo>'</mo></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<mfrac><mrow><mi>&mu;</mi><mo>'</mo></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
</mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<mfrac><mrow><mi>&nu;</mi><mo>'</mo></mrow>
<mrow>
<msup><mrow><mi>B</mi></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow>
</mfrac>
</mrow></math> is a magnetic
field of sorts.

<div class="p"><!----></div>
3° The postulate of relativity would compel us to adopt solution
(11), or solution (14), or any solution at all among those 
derived on the basis of the first remark. However, the first
question to ask is whether or not these solutions are compatible with
astronomical observations. The deviation from Newton's law is of the
order of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow><mi>&xi;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></math>, i.e., 10000 times smaller than if it were of the
order of 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&xi;</mi></mrow></math>, i.e., if the propagation were to take place with the
velocity of light, <em>ceteris non mutatis</em>; consequently, it is 
legitimate to hope that it will not be too large. To settle this
question, however, would require an extended discussion.

<div class="p"><!----></div>
<br />Paris, July, 1905.

<div class="p"><!----></div>

<div align="right">  H. Poincaré
</div>

<div class="p"><!----></div>
<hr /><h3>Footnotes:</h3>

<div class="p"><!----></div>
<a name="tthFtNtAAB"></a><a href="#tthFrefAAB">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>1</mn></mrow>
</msup>
</mrow></math></a>Translated by Scott Walter from <em>
      Rendiconti del Circolo Matematico di Palermo</em> 21, 1906,
    129-176. First published in J. Renn and M. Schemmel (eds.), <em>The
      Genesis of General Relativity Vol.&#x00A0;3: Theories of Gravitation in
      the Twilight of Classical Physics; Part I</em> (Boston Studies in
    the Philosophy of Science 250), 253-271, Springer, 2007.
The original notation is faithfully
    reproduced, including the use of "
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>d</mi></mrow></math>" for both ordinary and
    partial differentiation. The translator's footnote calls are
    bracketed. For alternative translations of Poincaré's memoir see C. W. Kilmister
    (<em>Special Theory of Relativity</em>, Oxford: Pergamon, 1970,
    145-185), and H. M. Schwartz (<em>American Journal of
      Physics</em> 39:1287-1294; 40:862-872, 1282-1287).
<div class="p"><!----></div>
<a name="tthFtNtAAC"></a><a href="#tthFrefAAC">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></math></a>Langevin was anticipated by Mr.&#x00A0;Bucherer of Bonn, who
  earlier advanced the same idea. (See: Bucherer, <em>Mathematische
    Einführung in die Elektronentheorie,</em> August, 1904. Teubner,
  Leipzig).
[Translator's note: the foregoing is Poincaré's footnote.]
  
<div class="p"><!----></div>
<a name="tthFtNtAAB"></a><a href="#tthFrefAAB">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>1</mn></mrow>
</msup>
</mrow></math></a>The
  original reads: "
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<mfrac><mrow><mn>4</mn></mrow>
<mrow><mn>3</mn></mrow>
</mfrac>
<mi>&pi;</mi>
<msup><mrow><mi>r</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></math>".
<div class="p"><!----></div>
<a name="tthFtNtAAC"></a><a href="#tthFrefAAC">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>2</mn></mrow>
</msup>
</mrow></math></a>The original reads: 
  "
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>&lambda;</mi><mo>'</mo><mo>=</mo>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mn>2</mn></mrow>
</msup>
<mi>&rho;</mi><mo>'</mo></mrow></math>".
<div class="p"><!----></div>
<a name="tthFtNtAAD"></a><a href="#tthFrefAAD">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>3</mn></mrow>
</msup>
</mrow></math></a>The original reads: "
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>D</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mo>'</mo><mo>=</mo>
<msup><mrow><mi>&ell;</mi></mrow><mrow><mo>-</mo><mn>2</mn></mrow>
</msup>

<msub><mrow><mi>D</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
</mrow></math>".
<div class="p"><!----></div>
<a name="tthFtNtAAE"></a><a href="#tthFrefAAE">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>4</mn></mrow>
</msup>
</mrow></math></a>The original reads: "à l'instant 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math>".
<div class="p"><!----></div>
<a name="tthFtNtAAF"></a><a href="#tthFrefAAF">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>5</mn></mrow>
</msup>
</mrow></math></a>The original reads "
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>x</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>y</mi></mrow></math>, 
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msub><mrow><mi>&delta;</mi></mrow><mrow><mn>1</mn></mrow>
</msub>
<mi>z</mi></mrow></math>, 1."
<div class="p"><!----></div>
<a name="tthFtNtAAG"></a><a href="#tthFrefAAG">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>6</mn></mrow>
</msup>
</mrow></math></a>The original reads
  "
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow><mi>t</mi></mrow></math> pourrait être négatif."
<div class="p"><!----></div>
<a name="tthFtNtAAH"></a><a href="#tthFrefAAH">
<math xmlns="http://www.w3.org/1998/Math/MathML">
<mrow>
<msup><mrow></mrow><mrow><mn>7</mn></mrow>
</msup>
</mrow></math></a>The original has (4) instead of
  (7).
<br /><br /><hr /><small><a href="/poincare/">Archives Henri Poincaré</a> (CNRS, UMR 7117)</small>
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